# Help to combine data (solved)

**URL:** <https://community.parabola.io/t/help-to-combine-data-solved/575>\
**Category:** Ask a question\
**Created:** [May 23, 2020, 4:56am UTC](https://community.parabola.io/t/help-to-combine-data-solved/575 "2020-05-23T04:56:32Z")\
**Posts on this page:** 2\
**Page:** 1

<div class="post-metadata">

**Author:** ![yong](https://avatars.discourse-cdn.com/v4/letter/y/b487fb/32.png) [@yong](https://community.parabola.io/u/yong)\
**Post date:** [May 23, 2020, 4:56am UTC](https://community.parabola.io/t/help-to-combine-data-solved/575/1 "2020-05-23T04:56:32Z")

</div>

Guys, I’m triyng to merge data coming from my existing database before importing into [bubble.io](http://bubble.io) but there are some rows that I would rather not include. Can’t find a way to filter those out.  
 ![Untitled](https://us1.discourse-cdn.com/flex020/uploads/parabola/original/1X/3a902a113c796ef08b27654ab4e6e41b61f45940.jpeg)

For item with variants, I would like to keep the rows of variants and filter out the first rows.  
For item without variants, then I would just keep the first row.  
Can anyone suggest a proper method? been all over these but still couldn’t figure out with my limited skills

Thanks heaps

---

<div class="post-metadata">

**Author:** ![sachi](https://sea2.discourse-cdn.com/flex020/user_avatar/community.parabola.io/sachi/32/10_2.png) [@sachi](https://community.parabola.io/u/sachi)\
**Post date:** [May 26, 2020, 4:06pm UTC](https://community.parabola.io/t/help-to-combine-data-solved/575/2 "2020-05-26T16:06:14Z")

</div>

Hi @yong! I would use the Row Filter step to accomplish this: [https://parabola.io/transforms/row-filter](https://parabola.io/transforms/row-filter)

I would use two separate Row Filter steps to create two separate branches - one for when variants exist and another for when variants are blank.

Hope that makes sense. Let me know how that goes!